To write this word is a total mess, but to write the first 63 characters, this you can do.
Write an "a" every 2 spaces or (21) spaces. This should look like this:
a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a_a
Then, from the first unoccupied space, write a "b", every 4 spaces (22) this time:
aba_aba_aba_aba_aba_aba_aba_aba_aba_aba_aba_aba_aba_aba_aba_aba
Repeat this last step, but with the "c", and now every 8 spaces (23) .
abacaba_abacaba_abacaba_abacaba_abacaba_abacaba_abacaba_abacaba
If you continue the pattern, this you should get:
abacabadabacaba_abacabadabacaba_abacabadabacaba_abacabadabacaba
abacabadabacabaeabacabadabacaba_abacabadabacabaeabacabadabacaba
abacabadabacabaeabacabadabacabafabacabadabacabaeabacabadabacaba
Of course, if you continue this until the "z", you will get a word (227)-1 characters long, which is 134,217,727 letters long!
And if you include all the character in the Unicode (the majority are Chinese characters and some are just representations as " ", but still, no discussing about that), the epic number of 109,449 you get:
5.40785978562894540705755027563290385780481607 × 1032947 letters!!!
But what does this apply to?
The Sierpiński Gasket!
Every time you see a black square, write "a", if you see a little white triangle, write "b", a bigger white triangle, "c"... etc.
And if all the "a"s in the triangle are one color, and the "b"s other... you get a colorful Sierpiński! (but that's another thing...)
And to really celebrate Sierpiński and the abacaba, I made the "rainbow gasket"!
Cool, huh?
-The Roaring Thunder
No hay comentarios:
Publicar un comentario